?? ????? ??? ??? ???? ??? ???? ???? ??? ??. ???? ?? ?? ?? ?? ??? ???? ?? ?? ?? ???!
?? ??? ??? ????? ??? ??? ????? ????? ??? ?? ?? ?? ?? ?? ?? ??? ?????? ??.
????? ???? ??????? ?????? ??? ????? ??????? ????? ??? ??? ????? ???? ?? ????? ????? ??????? ?? ?? ??? ????? ??? ???
????? ????? ???? ????? ?? ???? ?????? ???? ?????? ???? ??? ????? ??? ????? ???? ????? ?? ?????
![?? ?? ??? ?? ?? ?? ?????(pic1)](/uploads/allimg/20240805/3-240P51S523362.png)
???? ?? ?? ?? TR ???? ?? ??? ????? ???? ??????? ?? ????? ????? ?????? ?? borrowed tools ?? ????
![?? ?? ??? ?? ?? ?? ?????(pic2)](/uploads/allimg/20240805/3-240P51S523B0.png)
?? ?? ???? ?? ?? ??? ??? ???? ?????????? ?? ???? ??? ??? ???? ??
![?? ?? ??? ?? ?? ?? ?????(pic3)](/uploads/allimg/20240805/3-240P51S5241V.png)
???? ?? ???? ?? ???? ????? ?? ????? ??? ?????? ???? ??: ???? ?? ?????? ??? ????? per layer? ???? ??? ????? ??? ????? ??? ????? ??? ?? ????? ???? ??????
???? ????? ??? ?????? ???? ???? ???? ?????? ?? ???? ???:
![?? ?? ??? ?? ?? ?? ?????(pic4)](/uploads/allimg/20240805/3-240P51S524645.png)
??? ???? ?? ??? ?? ??? ?? ???? ???? ?? ?? ???? ??????? ??????? ??????? ???? ??? ?? ????? AB ??? ?? ?????? ???? ?? ????? ??? ?? ??? ?? ??? ???? ???? ???? ????? ????? ??? ??????? ?? ???? ????? ??.
??? ????? ????? ??? ???? X ?? ????? ??? Z ?? ??? ?? ???? ?? ?????? ??? ????? ??? ?? ????????? ????? ?? ???? ???? ??? ???? TAN15=AC/BC
?? ?? ?? ??? ????? ???? ???: AC=TAN15 * BC
?? ????? ??? ??? ??. ?? ?? ??? ?????????? ???? ???? BC ?? ???? ????? ?? ????? ??? AC ?? ????? ?? ????? ??? ????? ??? ??? ??? Tr ???? ???? ???????? ?? ??? ?????? ???? ??.
?? ??? ?? ????? ?? ??? ????? ???? ?? ?? ??? ???? ?? ????? ??? ?? ?????? ?? ????
?????? ????? ????? ?? ????? ?? ?? ???? ?? ??? ??? ???? ????
?????? ?? Tr ???? ???? ?? ??? ??? ??? ???? ?? ???? ??.
????? ?????? ??? ??? ??? ??? ??? ?? 2? (????? ??? ????? ???? ??? ??? ??? ??? ??? ??? ??? ??? ??? ????? ???? ??? ?? ????? ???? ?? ????? ???? ????? ??)
???? ?? ?? ?? TR100 * 12 ????? ???? ?????? ?????? ?? ??? ???:
![?? ?? ??? ?? ?? ?? ?????(pic5)](/uploads/allimg/20240805/3-240P51S52A61.png)
???? ???? ?? ????? ??? ?????? ???? ??? ?? ????? ???? ?? ???? ??
#2 ??? ?? ????? ?? ????? ???? ??? ?? ???? ?? ???? ??
#5 ???? ?? ?? ????? ?? ????? ???? ??? ?? ???? ??????? ?? ???? ?? ?? ???? ???? ???? ????? ??
#5= 4.12+2*TAN[15]*#2
?????? ????? ?? ????? ??? ??? ????? ??? ????? ??? ?? ????? ????? ??:
Tooth base width+2 x slope width - tool width.
?? ???? # 5=4.12+2 * TAN [15] * # 2-2
???? ??? ?? ?? ????? ?? ??? ??? ??? ??????? ?? ??? ????? ???
T0101
S300 M13
G0X100Z12
#2=6.5
WHILE [# 2GT0] DO1
#2=# 2-0.1
IF [# 2LE0] THEN# 2=0
#3=87+2 * # 2 (since # 3 is assigned a value of 6.5 and the first cut is made at the larger diameter of the thread, the smaller diameter plus the height of both teeth equals the larger diameter. When the value of # 2 changes, it means that the larger diameter also changes, thus achieving layered cut)
Z12
G0X # 3
G32Z-80.F12 (???? ???)
G0X102 (retraction)
Z12
#5=4.12+2 * TAN [15] * # 2-2
#6=# 5/2
Z [12+# 6] (???? ??? ????? ???? ?? ??? ???? ??? ????? 6 ??? ???? ?????? ???? ????? ???? ???? ?? ????? ??)
G0X#3
G32Z-80.F12
G0X102
Z12.
Z [12 - # 6] (???? ??? ????? ?? ??? ???? ??? ??? ???? ??? ?? ??? ???? ?? ?? ????? ????? ??? ???? ?? ????? ??)
G0X#3
G32Z-80.F12
G0X102
Z12.
END1
G0X200.
Z200.
M30
![?? ?? ??? ?? ?? ?? ?????(pic6)](/uploads/allimg/20240805/3-240P51S52J52.png)